php 实现日历

PHP 实现日历的方法

使用 PHP 可以轻松实现一个日历功能，以下是几种常见的实现方式：

基础日历实现

function generateCalendar($year, $month) {
    $firstDay = mktime(0, 0, 0, $month, 1, $year);
    $daysInMonth = date('t', $firstDay);
    $firstDayOfWeek = date('w', $firstDay);

    echo "<table border='1'>";
    echo "<tr><th>Sun</th><th>Mon</th><th>Tue</th><th>Wed</th><th>Thu</th><th>Fri</th><th>Sat</th></tr>";

    echo "<tr>";
    for ($i = 0; $i < $firstDayOfWeek; $i++) {
        echo "<td></td>";
    }

    $currentDay = 1;
    while ($currentDay <= $daysInMonth) {
        if (($currentDay + $firstDayOfWeek - 1) % 7 == 0 && $currentDay != 1) {
            echo "</tr><tr>";
        }
        echo "<td>$currentDay</td>";
        $currentDay++;
    }

    echo "</tr></table>";
}

generateCalendar(2023, 11);

使用 DateTime 类实现

function createCalendar($year, $month) {
    $date = new DateTime("$year-$month-01");
    $daysInMonth = $date->format('t');
    $firstDay = $date->format('w');

    echo "<table border='1'>";
    echo "<tr><th>Sun</th><th>Mon</th><th>Tue</th><th>Wed</th><th>Thu</th><th>Fri</th><th>Sat</th></tr>";

    echo "<tr>";
    for ($i = 0; $i < $firstDay; $i++) {
        echo "<td></td>";
    }

    $dayCount = 1;
    while ($dayCount <= $daysInMonth) {
        if (($dayCount + $firstDay - 1) % 7 == 0 && $dayCount != 1) {
            echo "</tr><tr>";
        }
        echo "<td>$dayCount</td>";
        $dayCount++;
    }

    echo "</tr></table>";
}

createCalendar(2023, 11);

带导航功能的日历

function calendarWithNavigation($year = null, $month = null) {
    $currentYear = $year ?? date('Y');
    $currentMonth = $month ?? date('m');

    $prevMonth = $currentMonth - 1;
    $prevYear = $currentYear;
    if ($prevMonth < 1) {
        $prevMonth = 12;
        $prevYear--;
    }

    $nextMonth = $currentMonth + 1;
    $nextYear = $currentYear;
    if ($nextMonth > 12) {
        $nextMonth = 1;
        $nextYear++;
    }

    echo "<div style='text-align:center;'>";
    echo "<a href='?year=$prevYear&month=$prevMonth'>Previous</a> ";
    echo date('F Y', mktime(0, 0, 0, $currentMonth, 1, $currentYear));
    echo " <a href='?year=$nextYear&month=$nextMonth'>Next</a>";
    echo "</div>";

    generateCalendar($currentYear, $currentMonth);
}

calendarWithNavigation($_GET['year'] ?? null, $_GET['month'] ?? null);

带事件标记的日历

function calendarWithEvents($year, $month, $events = []) {
    $firstDay = mktime(0, 0, 0, $month, 1, $year);
    $daysInMonth = date('t', $firstDay);
    $firstDayOfWeek = date('w', $firstDay);

    echo "<table border='1'>";
    echo "<tr><th>Sun</th><th>Mon</th><th>Tue</th><th>Wed</th><th>Thu</th><th>Fri</th><th>Sat</th></tr>";

    echo "<tr>";
    for ($i = 0; $i < $firstDayOfWeek; $i++) {
        echo "<td></td>";
    }

    $currentDay = 1;
    while ($currentDay <= $daysInMonth) {
        if (($currentDay + $firstDayOfWeek - 1) % 7 == 0 && $currentDay != 1) {
            echo "</tr><tr>";
        }

        $dateKey = "$year-$month-$currentDay";
        $eventMark = isset($events[$dateKey]) ? "<br><small>" . $events[$dateKey] . "</small>" : "";
        echo "<td>$currentDay$eventMark</td>";
        $currentDay++;
    }

    echo "</tr></table>";
}

$sampleEvents = [
    '2023-11-15' => 'Meeting',
    '2023-11-20' => 'Birthday'
];

calendarWithEvents(2023, 11, $sampleEvents);

这些方法提供了不同复杂程度的 PHP 日历实现，可以根据具体需求选择适合的方案或进行组合使用。